i can't do anything right i always hurt ppl and its the only thing i am good at...i'm not proud of it but maybe it's for the best that everyone leave me...i would leave me too...

no don't say that I love you

Awe, don't think that. If I was your friend, I wouldn't leave you, and besides I feel the same way all the time. You just have to remind yourself that your worth having people to talk to and people who love you...even if you don't know they do

You don't mess up everything, it just feels like it. And if you really think all your doing is hurting people, just know that even if you do one little thing wrong, or even a giant thing that's wrong, people won't stop loving you...trust me, I've done A LOT of bad things I my short lifetime, I just try not to bringing them up because it brings me down.

I'm Jessie, want to be friends? I hope this helped, I feel bad that there's  nothing else I can do to help

the range of a function is the range of y-values for which it is defined, or exists. given that we are only looking at the y-values, we can already discount the first two answers as they deal with the domain of the function (range of x-values).

now, what we need to do is find the smallest and highest y-values for which the function is defined. if you'd like, you could take a ruler and start at the very bottom of the graph, find the lowest point, then move the ruler higher and higher until you reach the highest point. doing so either in your head or with an actual ruler, we can see that the lowest y-value is -5 and the highest y-value is -1.

the question now remains as to whether they are included in the range (fourth answer) or excluded (third answer). the key here is to recognise whether they are marked with an open or a closed circle. since both (-2, -5) and (2, -1) are marked with a closed circle, they are points that exist on the graph and are thus included in the range (note that if they were marked with an open circle like (4, -2) then that would signify that there is a break in the graph at that point).

thus, the fourth answer, (y | -5 ≤ y ≤ -1), is correct.

also note that usually it is good practice to scan your eye inbetween the highest and lowest point for any breaks in the graph - we do have one here at (4, -2), however -2 is still included in the range because there is another point that is included in the graph with the same y-value, ie. point (1, -2).

i hope that but if you require any further explanation don't hesitate to comment below.