I need help with this. Mostly just 2a and 2b.

2a. A(t) = π(70 + 6t)^2 (Let t = 2 hours)

     A(2) = π(70 + 6(2))^2 = 6724π

     Now let t = 0 hours (result from part 1)

     A(t) = π(70 + 6(0))^2 = 4900π

     Average rate = 6724π - 4900π/2-0 = 912π

     912π area covered per hour

2b. Let t = 1/2 hours, A(t) = π(70 + 6(1/2))^2 = 5329π,

     Let t = 0 hours - result from last time was 4900π,

     Average rate =  5329π - 4900π/1/2 - 0 = 858π

     858π area covered per hour

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation: