Carlos performed a transformation on trapezoid EFGH to create E′F′G′H′, as shown in the figure below: A four quadrant coordinate grid is drawn. Trapezoid EFGH with coordinates are drawn at E negative 6, negative 4. F is at negative 4, negative 4. G is at negative 2, negative 6. H is at negative 7, negative 7. Trapezoid E prime F prime G prime H prime with coordinates are drawn at E prime negative 4, 6. F prime is at negative 4, 4. G prime is at negative 6, 2. H prime is at negative 7, 7.

What transformation did Carlos perform to create E′F′G′H′?

Rotation of 270° clockwise about the origin
Reflection across the x-axis
Rotation of 90° clockwise about the origin
Reflection across the line of symmetry of the figure

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step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

the answer to your question is b.