Write an equation in slope-intercept form of the line that passes through the points (-2, - 11) and (3,9). The equation is y=

y = 4x - 3

Step-by-step explanation:

(-2, -11) & (3, 9)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(9 - (-11)) / (3 - (-2))

Simplify the parentheses.

= (20) / (5)

Simplify the fraction.

20/5

= 4

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = 4x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (3, 9). Plug in the x and y values into the x and y of the standard equation.

9 = 4(3) + b

To find b, multiply the slope and the input of x(3)

9 = 12 + b

Now, subtract 12 from both sides to isolate b.

-3 = b

Plug this into your standard equation.

y = 4x - 3

This is your equation.

Check this by plugging in the other point you have not checked yet (-2, -11).

y = 4x - 3

-11 = 4(-2) -3

-11 = -8 - 3

-11 = -11

Your equation is correct.

Hope this helps!

i'm not sure i quite understand, could you provide more information?

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.