Convert (-5√3,0) into polar form in radians in terms of π over the interval 0≤theta<2π

z =  5√3(cos 0 + isin0)

Step-by-step explanation:

Convert (-5√3,0) into polar form in radians in terms of π over the interval 0≤theta<2π

The rectangular form is expressed as z = -5√3 + 0i

z = √(-5√3)² + 0²

z = √(25(3))

z = √75

z = 5√3

Get the argument

theta = tan^-1 0/-5√3

theta = tan^-10

theta = 0 degrees

Hence the polar form is expressed as z = r(cos theta + i sintheta)

z =  5√3(cos 0 + isin0)

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)