A six-sided die is rolled. What is the probability of landing on a number less than 3? Put our answer in simplest form.

1/3

Step-by-step explanation:

2/6

1/3

Probability of any one face to turn up is 1/6,

The probability of any above 3 is 3/6,

The probability of even number is also 3/6

So the probability of either above three or even outcome is 1/6(3/6 + 3/6)=1/6, since both events are independent of the any face event and both events are mutually exclusive.

NB:If the two events are not mutually exclusive, then

P(A) is the total event, P(B) the probability of any face above 3 and P(C) probability of any face an even number, then the Bayesian prediction formula is P(B|C) the probability of the event B occuring while C occurs is equal to (PC|P(B))/(P(B)+P(C), where P(C|B) is probability of C occuring at B.

So P(B|C)=(1/3 * 1/3)/(1/3 + 1/3) =(1/9)/(2/3) = 3/18= 1/6.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.