In a city, 49% of the adults are male. 24% of the adults are male and rent action-movie dvds, and 10% of the adults are female and rent action-movie dvds. if an adult is randomly selected for a survey, what is the probability that the adult rents action-movie dvds, given that the adult is female?

0.20

0.37

0.43

0.59

0.15

0.20

Step-by-step explanation:

Data:

A: the adult is a male, P(A) = 0.49

B: the adult rent action-movie DVDs

C: the adult is a female,  P(C) = 1 - P(A) = 1 - 0.49 = 0.51  

24% of the adults are male and rent action-movie DVDs, then P(A ∩ B) = 0.24

10% of the adults are female and rent action-movie DVDs, then P(C ∩ B) = 0.10

The conditional probability of B (the adult rents action-movie DVDs) given C (the adult is female) is computed as follows:

P(B|C) = P(C ∩ B)/P(C) = 0.1/0.51 = 0.2

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

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step-by-step explanation: