Please help

y = (-1/2)x + 2

Step-by-step explanation:

take two points on the line to find your slope (you can choose any two points on the line, I chose these two): (0,2) and (4,0)

m = (0-2) / (4-0)

m = -1/2

therefore, your slope is -1/2

look for the y-intercept, this is b

b = 2

y = mx + b

plug in the variables

y = (-1/2)x + 2

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

the answer is simply just 6n add the two together as they have an n