The area of a square with sides of length 12 is how many square units greater than the area of a square with sides of length 8?

Select one:
A. 80
B. 90
C. 100
D. 110

The answer is A. You have to take the areas of the 2 squares and then subtract them.

12×12=144u². 144-64=80u²

8×8=64

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.