A box is 14 in.​ high, 18 in.​ long, and 6 in. wide. What is the longest poster you could fit in the​ box? Use pencil and paper. Explain why you can only fit one​ maximum-length poster in the box but you can fit multiple ​22-in. posters in the same box.

- (2, -7)

- lines r and s and lines t and u must be parallel

there still no table

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²