1. At time t > 0, a particle moving in the xy-plane has velocity vector given by v(t) = (3t2,7t). What is the acceleration vector of the particle at time t = 2?

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step-by-step explanation:

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

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