A certain bacteria triples in a Petri dish every hour. Which formula should be used to determine the bacteria after x hours assuming uninhibited growth and there was initially 500 colonies. a
500\ \left(1.03\right)^x

b
500\ \left(3\right)^x

c
500\ \left(2\right)^x

d
500\ \left(1.02\right)^x

500(3)^x

Step-by-step explanation:

Got it right on edge

answer: ur v dumb

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15