A person invests 9000 dollars in a bank. The bank pays 6.5% interest compounded daily.
To the nearest tenth of a year, how long
must the person leave the money in the bank
until it reaches 31100 dollars?

19 years approx

Step-by-step explanation:

Given dta

P= $9000

r= 6.5%

A= $31100

Calculate time, solve for t

t = ln(A/P) / r

substitute

t= ln(31100/9000)/0.06.5

t= ln(3.45)/0.06.5

t= 1.23/ 0.065

t= 18.92

Hence the time is 19 years approx

3333333333333333333333333333333333333333333333

step-by-step explanation:

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.