Find the total area the regular pyramid.

T. A. =

20 +4√2

Step-by-step explanation:

Find the total area the regular pyramid = A + 1/2ps

A is the Base area

p is the perimeter of the base

s is slant height

A = 1/2 * 4 * 4

A = 16/2

A = 8

p = 4 + 4 + (√4^2+4^2)

p = 8 + √32

p = 8 + 4√2

s = 4

Substitute

TSA = 8 + 8 + 4√2 + 4

TSA = 20 +4√2

Hence the total surface area is 20 +4√2

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.