On the first day of ticket sales the school sold 8 senior citizen tickets and 1 child ticket for a total of $97. The school took in $102 on the second day by selling 6 senior citizen tickets and 4 child tickets. Find the price of a senior citizen ticket and the price of a child ticket.

A senior citizen ticket costs $11, and a child ticket costs $9.

Step-by-step explanation:

Let s = price of 1 senior citizen ticket, and let c = price of 1 child ticket.

First day:

8s + c = 97

Second day:

6s + 4c = 102

We have a system of 2 equations in 2 unknowns.

8s + c = 97

6s + 4c = 102

We will use the addition method to solve the system.

Multiply both sides of the first equation by -4. Write the second equation below it and add the equations.

     -32s - 4c = -388

(+)     6s + 4c = 102

      -26s       = -286

Divide both sides by -26.

s = 11

Now substitute s with 11 in the first original equation and solve for c.

8s + c = 97

8(11) + c = 97

88 + c = 97

Subtract 88 from both sides.

c = 9

A senior citizen ticket costs $11, and a child ticket costs $9.

d

step-by-step explanation:

d

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x