4. The probability that I will go sailing today AND the fair six-sided die will come up even on the next roll is .3.
these events are independent, what is the probability that I will go sailing today?

Step-by-step explanation:

Let us consider P(A) to be the probability for the fact that I will go for sailing today

Likewise, P(B) will be the probability of a die to come up on an even number in the next roll.

Now, according to the question,

P(A and B) = 0.3

It is known to us that the probability of a die to land with an even number on its side up =  

Moreover, we are given with the fact that both P(A) and P(B) are independent.

∴ P(A and B) = P(A) × P(B)

⇒ 0.3 = P(A) × 0.5

⇒ P(A) =  = 0.6

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

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