Old MacDonald had a farm. On this farm he had some cows and chickens. When he “took stock” (counted), the farmer had 15 animals and 44 legs. How many cows and chickens did Old MacDonald have? PLS ANSWER

22

Step-by-step explanation:

Step-by-step explanation:

let x be chickens and y be cows

x+y=15

x=15-y

2x+4y=44, using x=15-y

2(15-y)+4y=44

30-2y+4y=44

2y+30=44

2y=14

y=7, since x=15-y

x=8

So there are 8 chickens and 7 cows.

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.