What are the coordinates of A after reflecting across the line x = 3? (2, 3) (3, 2) (3, 4) (3, -2)​

Here we can not see point A, so i will answer in a general way.

Let's suppose that point A is (a, b)

Now, if we do a reflection over a given line, the (perpendicular) distance between our original point to the line is the same as the distance between the reflected point and the line.

So for example if we have the point (x, y) and we do a reflection over the line x = k.

The distance between our point and the line is:

x - k

So the new point must be also at a distance of (x - k) from line x = k.

The only other point that meets this condition is (k - (x - k),  y) = (2k - x, y)

Now remember that point A is (a, b)

And we do a reflection over x = 3

The distance between our point and the line is:

D = I(a - 3)I

Then the reflection will be:

(3 - (a - 3), b) = (6 - a, b)

Where (a, b) where the original coordinates of point A.

the answer would be c:   ax + b = ax + c

step-by-step explanation:

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,