I need help with this question. Is anyone able to explain and answer it?
Thank you

m∠OPT = 32°

Step-by-step explanation:

From the picture attached,

m∠OTP = 90°

[Property: Tangent from a point outside the circle and radius of the circle are perpendicular]

QT║OP [Given]

OT is a transversal line,

Therefore, m∠QTO = m∠TOP = 58° [Interior alternate angles]

By applying triangle sum theorem in ΔTPO,

m∠OPT + m∠TOP + m∠OTP = 180°

m∠OPT + 90° + 58° = 180°

m∠OPT = 180° - 148°

m∠OPT = 32°