The height, in feet, after x seconds of an object launched straight up can be found by the function h(t) = ‐16t² + v0t + h0 , where v0 is the initial velocity of the object and h0 is the initial height. If a ball is thrown straight up into the air from a height of 6ft and an initial velocity of 29 ft/s, after how many seconds will the ball hit the ground?

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

answer: 12,000

step-by-step explanation: first you ar e supposed to add. then multiply then subtract

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9