The polynomial −16t2+v0t+s0 represents the height (in feet) of an object, where v0 is the initial vertical velocity (in feet per second), s0 is the initial height of the object (in feet), and t is the time (in seconds). Write a polynomial that represents the height of the object. Then find the height of the object after 1 second.

at 1.2 seconds, the object will be in a position less than 128 feet.

Step-by-step explanation:

No explantion because it was too big. Sorry.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)