What is the slope line of (12, -8) and (2,3) pls help ;-;

-1.1

Step-by-step explanation:

Slope (m) =  

ΔY

ΔX

=  

11

-10

=-1.1

θ =  

arctan(ΔY) + 180°

ΔX

=132.27368900609°

ΔX = 2 – 12 = -10

ΔY = 3 – -8 = 11

Distance (d) = √ΔX2 + ΔY2 = √221 = 14.866068747319

Equation of the line:

y = -1.1x + 5.2

or

y =  

-11x

10

+  26

5

When x=0, y = 5.2

When y=0, x = 4.7272727272727