A triangle with area 40 square inches has a height that is four less than six times the base. Find the base and height of the triangle

A = 1/2bh

Step-by-step explanation:

40 = (.5)(6x - 4)(x)

40 = (3x-2)(x)

40= 3x^2 - 2x

3x^2 -2x - 40 =0

3x^2 - 12x + 10x - 40 = 0

3x(x - 4) + 10(x -4) = 0

(3x + 10)(x - 4) = 0

x = {4 , - 10/3}

x = 4 , b = 20. h = 4

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

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