Please please help I’m failing quadrilateral EFGH has vertices at e (10,4) f (16,4) g (16,10) and h (10,10). Based on the properties of the diagonals is quadrilateral EFGH a rectangle rhombus or square use the distance and slope formulas to prove your conclusion show your work.

It's a square; vertice f is 6 units to the right of vertice e and g is 6 units above f, and h is 6 units to the left of g. This means there are four sides of equal length, with equal angles.

do you need more than that?

the least common denominator is 40

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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