The path of a toy rocket fired into the air can be represented by the equation h= -16t^2+75t. What is the height of the rocket after 3 seconds?

81 units

Step-by-step explanation:

Given data

We are given the function for the height, the height is a function of time t

h=-16t^2+75t

Hence for t= 3 , let us substitute and find the height h

h=-16(3)^2+75(3)

h= -16*9+ 225

h= -144+ 225

h= 81

Hence the height at 3 seconds is 81 units

12/11c

or

12

c

11

i think it is 70

step-by-step explanation: