can someone help please? :< brainliest to whoever answers first(50 points) correct answers please! :(

y=-4x+7

Step-by-step explanation:

Test all the values of x given and compare the value of y as shown.

when x=-3

y=19

y=-4*-3+7=19√

when x=-2

y=15

y=-4*-2+7=15√

when x=-1

y=11

y=-4*-1+7=11√

when x=0

y=7

y=-4*0+7=7√

when x=1

y=3

y=-4*1+7=3√

Now you can give the kind person who was able to answer your problem! :)

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)