Given the points M(−6,−4) and T(9,16) find the y-coordinate of the point Q on the directed line segment MT so that MQ:QT=2:3.

8

Step-by-step explanation:

Given the coordinates M (-6, -4) and T (9, 16)

If the coordinates are divided in the ratio 2:3 then a = 2, b = 3

The y coordinate of the point Q will be expressed as;

Y = ay1+by2/a+b

From the coordinates, y1 = -4 y2 = 16

Y = 2(-4)+3(16)/2+3

Y = -8+48/5

Y = 40/5

Y = 8

Hence the y-coordinate of the point Q is 8

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.