Which polynomial correctly combines the like terms and expresses the given polynomial in standard form? 9xy3 – 4y4 – 10x2y2 + x3y + 3x4 + 2x2y2 – 9y4

3x4 – 8x2y2 + x3y + 9xy3 – 13y4
3, x, 4, – 8, x, 2, y, 2, + , x, 3, y, + 9, xy, 3, – 13, y, 4

–13y4 + 3x4 – 8x2y2 + x3y + 9xy3
–13, y, 4, + 3, x, 4, – 8, x, 2, y, 2, + , x, 3, y, + 9, xy, 3

–13y4 + x3y – 8x2y2 + 9xy3 + 3x4
–13, y, 4, + , x, 3, y, – 8, x, 2, y, 2, + 9, xy, 3, + 3, x, 4

3x4 + x3y – 8x2y2 + 9xy3 – 13y4

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

cant

step-by-step explanation: there is no picture

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9