Um comerciante comprou um lote de cabos e quer colocá-los à venda em pedaços, o maior possível, com o mesmo comprimento e sem haver perdas. Sabendo que, os cabos têm comprimento de 96m, 60m e 84m, qual a medida dos pedaços a serem oferecidos aos clientes?

12

Step-by-step explanation:

The computation of the size of the customers is shown below:

Here we find the greatest common divisor of the given numbers

96, 60, 84 ÷ 2

48, 30, 42  ÷ 2

24, 15, 21 ÷ 2

12, 15, 21 ÷ 2

6, 15, 21 ÷ 2

3, 15, 21  ÷ 3

1, 5, 7 ÷ 5

1, 1, 7 ÷ 7

1, 1, 1

By this there are three numbers i.e. 2, 2 and 3

So, the lease common denominator is

= 2 × 2 × 3

= 12

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

what? that isnt a question

step-by-step explanation: