A quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, to the nearest hundredth? please help

7569.36

Step-by-step explanation:

Given that a quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, 

First convert 1.25 days to hours

1.25 × 24 = 30 hours

Using exponential equation

N = No ( 1 - R% )^t

Where N = new value of the quantity

No = initial value

R = rate

t = time

N = 7800 ( 1 - 0.001 )^30

N = 7800 ( 0.999 )^30

N = 7800 × 0.97043

N = 7569.36154

N = 7569.36 to the nearest hundredth.

Therefore, the value of the quantity after 1.25 days is 7569.36

what are the statments

step-by-step explanation:

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: