LESSON 7-2 Operations with Linear Functions Practice and Problem Solving: A/B Given the functions f(x) and g(x), find the function h(x) = f(x) + g(x). 1. f(x) = 3x - 2, g(x) = 12x + 5 2. fx) = -6x - 1, g(x) = 3x - 4 Given the functions f(x) and g(x), find the function k(x) = f(x) = g(x). 3. f(x) = 8x + 7, g(x) = 5x + 3 4. f(x) = 2x + 6, 9(x) = 4x + 11 Given the functions f(x) and g(x), find the function p(x) = f(x) g(x). 5. f(x) = -5, g(x) = -9x - 4 6. Xx) = , g(x) = 12x - 27 A company manufactures and sells slippers. The price it charges wholesalers is $18 per pair. The company has fixed annual costs of $30,000. In addition, it costs the company $4.50 to make each pair of slippers. Use this information for Problems 7–12. 7. Write the revenue function r(x), where x is the number of slippers sold in a year and r(x) is the total revenue from those sales. 8. Write the cost function c(x), where x is the number of slippers sold in a year and c(x) is the annual cost for the company.​

i am thinking c. sorry if im wrong .

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

a is the right answer

a c

step-by-step explanation: