How would I write an equation for a line with a slope of ²/³ that has a y-intercept at -2?

y = 2/3 x - 2

Step-by-step explanation:

The standard form of writing equation of a line is y = mx+b

m is the slope

b is the y-intercept

Given the following:

m = 2/3

b = -2

Substitute into the formula

y = mx+b

y = 2/3 x + (-2)

y = 2/3 x - 2

Hence the required equation is y = 2/3 x - 2

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