Find unknown sizes of angles

2a+110=180(co interior angle)

2a=180-110

a=70/2=35

2a=2×35=70

a=x=35 alternate angle

x+2a=y exterior angle of triangle is equal to the sum of two interior angle

35+70=y

y=105

x=a

(being alternate angles)

x+2a=110°

(Being sum of interior angles opposite to exterior angles)

or, a +2a =110°

or, 3a=110°

or, a=110°/3

therefore, a=36.67

Now;

2a = 2×36.67

= 73.34

the answer I solved is wrong please don't write it

,xzgv

step-by-step explanation:

; oqirjg'

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!