three consecutive odd integers are such that three times the smallest is 9 more than twice the largest find the three numbers​

https://www.wyzant.com/resources/answers/732264/three-consecutive-odd-integers-are-such-that-3-times-the-smallest-is-9-more

Step-by-step explanation:

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17, 19, 21

Step-by-step explanation:

let the 3 consecutive odd numbers be n, n + 2 and n + 4 , then

3n = 2(n + 4) + 9 ( 3 times smallest is 9 more than twice the largest )

3n = 2n + 8 + 9

3n = 2n + 17 ( subtract 2n from both sides )

n = 17

n + 2 = 17 + 2 = 19

n + 4 = 17 + 4 = 21

The 3 numbers are 17, 19, 21

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it