A bag contains 4 blue and 5 red counters. Two counters are chosen at random without replacement. What is the probability that the counters are both red?

P(both are red) = 5/18

Step-by-step explanation:

total counters = 9

red counters = 5

P(both red) = P(R1) n P(R2)

5/9 * 4/8 =5/18

5/9 because the red counters are 5 and the total number of counters are 9.

I multiplied by 4/8 because, after selecting the first red counter without replacement, the remaining is 4 and the total decreases to 8.

if she was to only spend a dollar she can get 1lb

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: