9 different names are put into a computer and one of the names is Kevin. a) On Saturday, the computer chooses 2 names at random. The computer is set so that the same name can be chosen twice. What is the probability that Kevin is chosen at least once?
b) On Sunday the computer is set so that the same name cannot be chosen twice. Work out the probability that Kevin is chosen.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

step-by-step explanation:

the answer is 128

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

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