Find the value of two numbers if their sum is 12 and their difference is 4. Systems of equations 8th grade math.

To solve this problem, we will setup a system.

We know that two numbers have a sum of 12 and a difference of 4.

So let's call our first number x and our second number y.

So we know that x + y = 12.

We can also say that x - y = 4.

Now rewrite the equations on top of each other.

Now we can use addition to solve this system.

When we add the equations together, the y's will cancel.

So we have 2x = 16.

Now divide both sides by 2 and x = 8.

Now plug an 8 back in for x in the first equation to find that y = 4.

So our numbers are 8 and 4.

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5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form