In this diagram, ABAC – AEDF. If the area of ABAC = 8 in2, what is the
area of AEDF?
D
E
3 in
F
B.
4 in
С
Area = [?] in?
Enter a decimal rounded to the tenths.

Area = 4.5 in.²

Step-by-step explanation:

Area of ∆BAC = 8 in.²

EF = 3 in.

BC = 4 in.

Since both triangles are similar, therefore,

Area of ∆BAC : Area of ∆EDF = BC² : EF²

Plug in the values into the equation

8/area of ∆EDF = 4²/3²

Area of ∆EDF = (8*3²)/4²

= 4.5 in²

{3 + i, 3 - i, 3, -1}

step-by-step explanation: