find the probility that number chose at random from tha integers between 5 and 16 inclusive is a multiple of 3 or a multiple of 2​

Numbers between 5 and 16 are:-

6, 7, 8, 9, 10, 11, 12, 13, 14 , 15 and 16.

Therefore, total number of outcomes =11

Numbers inclusive between 5 and 16 which are divisible by 2 or 3 are-

6 , 8, 9 ,10 ,12, 14 and 15.

Number of favourable outcomes = 7

Therefore, probability of getting a number which is either a multiple of 2 or 3 is:

p(e) = \frac{7}{11}p(e)=

11

7

HENCE, THE REQUIRED PROBABILITY IS = 7 / 11.

IF THIS IS RIGHT PLZ AKE ME BRAINLIANLIEST

Step-by-step explanation:

P(3)= All multiple of 3/Total outcome=4/11

P(2)= All the multiple of 2/Total outcome = 7/11

:):):):)

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!