A bank loaned out $20,000, part of it at the rate of 11% annual interest, and the rest at 10% annual interest. The total interest earned for both loans was $2,150.00. How much was loaned at each rate?

$8,000 was loaned at a 9% interest rate

Step-by-step explanation:

Ok, so we know the bank loaned part of the $17,500 at a 4% interest rate.  Lets call this loan amount x.  Then the rest of the 17,500 was loaned at a 9% interest rate.  Whatever this amount was, we can define it as 17,500 - x.  We also know that the total interest earned was $1,100.  With this information, we can form the following equation:

.04(x) + .09(17500 - x) = 1100

Multiply the .09 times the inside of the parentheses:

.04x + 1575 - .09x = 1100

Simplify:

-.05x + 1575 = 1100

-.05x = -475

x = 9500

Since x is originally the amount loaned at the 4% interest rate, we know that $9,500 was loaned at a 4% interest rate.

To figure out the other amount loaned at 9%, simply subtract 9,500 from 17,500 -- this gets us 8,000.  So $8,000 was loaned at a 9% interest rate.

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.