Abebe is 12 years old and his sister Aster is 2 years old. In how many years will Abebe be exactly twice as old as Aster?
can u give me equation for the above question plsss​

Abebe will be exact twice as old as Aster in 8 years.

Step-by-step explanation:

Since Abebe is 12 years old, and his sister Aster is 2 years old, there is a difference of 10 years between them (12 - 2). Therefore, the difference between the two implies that Abebe is exactly twice as old as her sister when she is 10 years old, and she is 20 years old (10 x 2 = 20).

Therefore, since 20-12 equals 8, Abebe will be twice as old as her sister Aster hers in 8 years.

like I said before Abebe will be exact twice as old as Aster in 8 years.

Since Abebe is 12 years old, and his sister Aster is 2 years old, there is a difference of 10 years between them (12 - 2). Therefore, the difference between the two implies that Abebe is exactly twice as old as her sister when she is 10 years old, and she is 20 years old (10 x 2 = 20).

Therefore, since 20-12 equals 8, Abebe will be twice as old as her sister Aster hers in 8 years.

Step-by-step explanation: but I’m not to sure on how to make the equation

add an image, and i will answer

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°