A rectangular lot is 125 yards long and 80 yards wide. Give the length and width of another rectangular lot that has the same perimeter but a larger area.

Step-by-step explanation:

perimeter=2(125+80)=2(205)=410 yards

let the length of new rectangle be x and y.

Perimeter=2(x+y)

2(x+y)=410

x+y=410/2=205 yards

y=205-x

area A=xy=x(205-x)=205x-x²

A is maximum at x=205/2

y=205-205/2=(410-205)/2=205/2

so x=205/2=102.5 yards

y=205/2=102.5 yards

4 puzzles in 3 hours

step-by-step explanation:

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: