A certain lottery requires players to select 4 different​ numbers, in any​ order, from 1 to 46 inclusive. How many different sets of 4 numbers can be​ chosen?

345025251

Step-by-step explanation:

Given

Total = 51

Numbers =7

Required

Determine number of selection

It's important that

- The first number can be any of the 51 numbers

- The second number can be any of the 51 numbers

- The third number can be any of the 51 numbers

- The fourth number can be any of the 51 numbers

And so on

Hence, number of selections is:

Selection= 51 * 51 * 51 * 51 * 51

Selectioin =51^5

Selection 345025251  ways

Give Brainliest

-1/2 +2

step-by-step explanation:

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^