Assume that the probability of a driver getting into an accident is 7.1%, the average cost of an accident is $14,886.0 , and the overhead cost for an insurance company per insured driver is $110 . What should the driver's insurance premium be?

$1166.91

Step-by-step explanation:

The following can be deduced from the question:

Average cost of an accident = $14,886.05

Probability of a driver getting into an accident = 7.1% = 7.1/100 = 0.071.

Overhead cost for insurance = $110

Therefore, the expected cost of an accident will be calculated as:

= Average cost of an accident × Probability of a driver getting into an accident

= $14,886.05 × 0.071

= $1056.91

Therefore, the driver's insurance premium will then be:

= $1056.91 + $110

= $1166.91

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

168

step-by-step explanation:

i am pretty sure that the answer is 168