Write the point-slope form of the line that passes through (1, -5) and is perpendicular to a line with a slope of 1. include all of your work in your final answer. type your answer in the box provided or use the upload option to submit your solution.

A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So if we have a slope of 1 or 1/1. our perpendicular line needs a slope of -1.

y - y1 = m(x - x1)
slope(m) = -1
(1,-5)...x1 = 1 and y1 = -5
now we sub...pay close attention to ur signs
y - (-5) = -1(x - 1)not done yet
y + 5 = -1(x - 1)...or it can also be written as : y + 5 = - (x - 1)

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!