Aubrey has a new art box in the shape of a rectangular rectangular prism. The box is 12 cm space, by 20cm, 5 cm the only thing in the art box is a new pink eraser with the dimensions shown below. What is the volume of the art box not taken up by the eraser?

By an online search, I've found that the dimensions of the eraser are:

4cm by 2cm by 0.5cm

First, we need to remember that for a rectangular prism of length L, width W, and height H, the volume is:

V = L*W*H

We know that the measures of the box are:

12cm by 20cm by 5cm

Then we can define:

L = 12cm

W = 20cm

H = 5cm

Then the total volume of the box is:

V = 12cm*20cm*5cm = 1200 cm^3

For the eraser, we will have:

L = 4cm

W = 2cm

H = 0.5cm

Then the volume of the eraser is:

v = 4cm*2cm*0.5cm = 4 cm^3

The volume of the box that is not taken up by the eraser is equal to the difference between the volume of the box and the volume of the eraser.

Then:

Volume not taken by the eraser = V - v = 1200cm^3 - 4cm^3 = 1196cm^3

stop cheating

step-by-step explanation: