A bag contains 14 blue, 6 red, 12 green, and 8 purple buttons. 25 buttons are removed from the bag randomly. How many of the removed buttons were red if the chance of drawing a red button from the bag is now 1/3?

1 button.

Step-by-step explanation:

Total buttons = 40

Total red buttons = 6

Total Buttons removed =25

Buttons left = 40–25 = 15

Let the red buttons left = x

1.)Then, the probability of red buttons after removing 25 buttons = x/15 outcome / Total outcome)

2.)Probability of red buttons in the bag after removing 25 buttons is 1/3 (As given in the question)

Comparing Statement 1.) & 2.) , We get

x/15 = 1/3

x = 5

So the red buttons left = 5

Total red buttons= 6

Red buttons removed = 6–5= 1

Hence, only 1 button was red in the 25 removed buttons

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d