If y varies inversely with the square of x, and y=6 when x=4, find y when x=0.1

9600

Step-by-step explanation:

y varies inversely with the square of x

y=k/(x^2)

for some non-zero constant k

y=6 when x=4

6=k/(4^2)

k=96

y=96/(x^2)

x=0.1

y=96/(0.1^2)

y=9600

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

sine

step-by-step explanation: