The diagram shows the sector of a circle with the centre O and radius 6cm. MN is a chord of the angle.
angle MON is 50 degrees

calculate the area of the shaded segment
give your answer to 3 significant figures

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN =

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN =

                                  = 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN =

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) =

PN = ONsin(25°)

     = 6sin(25°)

     = 2.536 cm²

cos(25°) =

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

                         = 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

                                             ≈ 1.92 cm²

i need a picture

step-by-step explanation:

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)