What is the standard error of a box with 5 tickets 1, 1, 2, 3, and 5 if we draw with replacement 100 times?

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

there is only one way to arrange all the eight relative to each other because they are not distinct. we have

now there are nine places to place an (and not more than one in one place).   because we have four symbols, we need to choose four of these nine places to insert an . order does not matter because the are not distinct.

thus there are 1 · c(9,4) ways, or, if we calculate it,

thus there are 126 ways to form such "words."